BRICK WORK CEMENT QUANTITY 1 M3 - CIVIL ENGINEER VIJAY TECHNICAL

How to calculate the number of bricks, cement and sand required for a brick wall 7 m long, 3.2 m high and 0.23 wide. The brick wall consists of a mortar joint with a cement-sand ratio of 1:6. Bricks measuring 230mm x 114mm x 76mm.

First calculate for 1 cubic masonry.Volume of bricks = 1 cmm.

Brick dimension = 230 mm x 114 mm x 76 mm

Brick Cement Sand Calculation

Volume of 1 brick without mortar = 0.23 m x 0.114 m x 0.076 m = 0.00199272 cu.Number of bricks required without mortar = (volume of bricks)/ (volume of 1 brick without mortar) = 1/ (0.00199272) = 502 no.

Add a 10 mm thick mortar joint

Brick dimension = 240mm x 124mm x 86mm.Volume of 1 brick with mortar = 0.24 m x 0.124 m x 0.086 m  = 0.00255936 cum Number of bricks needed with mortar = (volume of masonry)/ (volume of 1 brick with mortar) = 1/ (0.00255936) = 391 no.

Therefore. the number of bricks was reduced from 502 to 391 due to the presence of mortar.

Calculation of cement and sand Volume of mortar = volume of bricks – (volume of bricks without mortar x number of bricks needed with mortar) = 1 – (0.00199272 x 391) = 0.22084648 cum Therefore, we would like 391 bricks and 0.23 m of cement mortar per 1 m of brick.

Now we also need to find out how much cement and how much sand is needed for 0.23 cm3 of mortar. In my experience with Particle, the ratio of cement to sand used in a 230mm thick wall is 1:6.Wet volume of cement mortar = 0.23 m3. Dry volume of mortar = 0.23 x 1.33 = 0.3059 m3. C:S ratio = 1:6.

Calculation of cement

Cement in cum = (volume of mortar x ratio of cement) / (sum of ratio) = (0.3059 x 1) (1+6) = 0.3059/7 = 0.0437 m3 Cement in kilograms = 0.0437 x 1440 = 62.928 kg. Cement in a bag = 62.928 / 50 = 1.26 bags.

Calculation of sand

Sand in cum = (volume of mortar x ratio of sand) / (sum of ratio = (0.3059 x 6) (1+6) = 0.3059/7 = 0.2622 m3

In short, we need 1 cum brick;

Bricks = 391 no. Cement = 1.26 bags Sand = 0.2622 m3.

Now Material consumption for a brick wall 7m long, 3.2m high and 0.23m wide

Volume of brick wall = 7 x 0.23 x 3.2 = 5.152 cu. Material consumption The consumption of the Material must therefore be such that Cement = 1.26 bags x 5.152 = 6.5 bags.Sand = 0.2622 cm3 x 5.152 = 1.35 cm3. Bricks = 391 Bricks x 5,152 = 2015 Nos.

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